Category Archives: Math

Suz and Mike had a question

Problem Statement: If is bounded with finitely many discontinuities on then is Riemann Integrable on . Proof: Let be the number of discontinuities of on and let be such that for every . We know such an exists since is bounded. Since … Continue reading

Posted in Analysis, Math, Riemann Integrable | 2 Comments

Rudin- Ch. 3 #13

Problem Statement: Given and define the product to be where . Suppose that converges to absolutely and converges to absolutely. Prove that converges to a value absolutely. Proof: Since and converge absolutely we know that their product converges to (this is by … Continue reading

Posted in Absolute Convergence, Analysis, Math, Sequence, Series | Leave a comment

Rudin: Ch. 3 #8

Problem Statement: If converges and is monotonic and bounded, prove that converges. Proof: Since we are given that is bounded and monotonic we know there exists some such that . Let , then there exists some such that for every . Note that … Continue reading

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Winter 2008 #5

Problem Statement: Let . Prove is Riemann Integrable on and .  Proof: First note that each is continuous on and since is a sum of continuous functions it follows that is continuous on . Furthermore, since is a compact set it … Continue reading

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April 2009 #2

Problem Statement: Suppose is a real-valued differentiable function such that for every . Show there is at most one such that . Proof: Suppose to the contrary that there are two such values such that and . Wlog assume that . Since … Continue reading

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Spring 2008 #5

Problem Statement: Let be a sequence of continuous functions defined on and a real valued function defined on . (a) Prove if uniformly then and (b) Does this hold is pointwise? Prove or give a counter example. (a) Proof: We are given … Continue reading

Posted in Analysis, Continuity, Math, Uniform Convergence | 1 Comment

Spring 2004 #5

Problem Statement: Let be differentiable. Let such that and . If is between and then there exists such that . Proof: Wlog assume . Fix . Define . Then . Note that and since . and so for sufficiently close to , … Continue reading

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